用C语言编程序，按下列公式计算e的值（精度为1e-5）：e=1+1/1!+1/2!+1/3!+1/4!+…+1/n!

#include int main(){ int a; double b,c,sum=0; a=1; b=1; c=1; while(b >1e-5) { b=1.0/a; c=c*b; a++; sum+=c; } sum +=1; printf("e=%lf\n",sum); }