已知i为虚数单位,若a+i1?i是纯虚数,则实数a的值为(  )A.-2B.-1C.1D.

日期:2014-12-05 10:41:21 人气:2

已知i为虚数单位,若a+i1?i是纯虚数,则实数a的值为(  )A.-2B.-1C.1D.

a+i1?i=(a+i)(1+i)(1?i)(1+i)=a+i+ai+i22,∵复数a+i1?i是纯虚数,∴a-1=0,∴a=1.故选:C.
    A+
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