求C语言编程，e=1+1/1！+1/2！+1/3!+...+1/n!,精确度1e-6

#include using namespace std; int main() { int i=1; double e=1.0,d=1.0; while(d>=1e-6) { d=d/i; e+=d; i++; } cout<<"e的值为:"<<e<<endl; return 0; }