f(n)=sin nπ/6，n∈Z，求f(1)+f(2)+f(3)+……+f(2010)

f(1)=sin π/6=1/2 f(2)=sin π/3=√3/2 f(3)=sin π/2=1 f(4)=sin 2π/3=√3/2 f(5)=sin 5π/6=1/2 f(6)=sin π=0 f(7)=sin 7π/6=-1/2 f(8)=sin 4π/3=-√3/2 f(9)=sin 3π/2=-1 f(10)=sin 5π/3=-√3/2 f(11)=sin 11π&