若X1满足2X+2的x次方=5,x2满足2X+2log2(X-1)=5.则X1+X2等于?

日期:2013-09-20 15:22:10 人气:1

若X1满足2X+2的x次方=5,x2满足2X+2log2(X-1)=5.则X1+X2等于?

解:2X+2^x=5 x+2^(x-1)=2.5 2X+2log2(x-1)(2是底数)=5 x+log2(x-1)=2.5 其中y=2^(x-1)与y=log2(x-1)关于y=x-1对称 y=2.5-x与前面指数 对数曲线交点即为x1,x2. x1+x2为y=2.5-x,y=x-1交点横坐标2倍即3.5
    A+
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