(1+1/2+1/3...+1/100)×(1/2+1/3...+1/101)-（1+1/2+1/3+...1/101)×(1/2+1/3+...1/100)
(1+1/2+1/3...+1/100)×(1/2+1/3...+1/101)-（1+1/2+1/3+...1/101)×(1/2+1/3+...1/100)
日期：2022-04-10 12:39:31 人气：1
令(1/2+1/3+...1/100)=n
（1+1/2+1/3...+1/100)×(1/2+1/3...+1/101)-(1+1/2+1/3...+1/101)×（1/2+1/3+...1/100)
=(1+n)(n+1/101)-(1+n+1/101)n
（1+1/2+1/3...+1/100)×(1/2+1/3...+1/101)-(1+1/2+1/3...+1/101)×（1/2+1/3+...1/100)
=(1+n)(n+1/101)-(1+n+1/101)n