数1的3次方+2的3次方+3的3次方+4的3次方+5的3次方+..+2008的3次方的个位数是几？

n^3 = n(n+1)(n+2) - 3n(n+1) +n = (1/4)[n(n+1)(n+2)(n+3)-(n-1)n(n+1)(n+2)] -[n(n+1)(n+2)-(n-1)n(n+1)] +(1/2)[n(n+1) -(n-1)n] 1^3+2^3+...+n^3 = (1/4)n(n+1)(n+2)(n+3) -n(n+1)(n+2)+(1/2)n(n+1) = (1/4)n(n+1) [(n+2)(n+3)-4(n+2)+2 ] =