1/1×3+1/3×5+1/5×7…+1/97×99得多少，加过程。

1/(1×3)+1/(3×5)+1/(5×7)…+1/(97×99)的结果等于49/99。

解：1/(1×3)+1/(3×5)+1/(5×7)…+1/(97×99)

=1/2*(1-1/3)+1/2*(1/3-1/5)+1/2*(1/5-1/7)+...+1/2*(1/97-1/99)

=1/2*((1-1/3)+(1/3-1/5)+(1/5-1/7)+...+(1/97-1/9