考察一般项第k项: (2k)2/[(2k-1)(2k+1)] =4k2/(4k2-1) =(4k2-1+1)/(4k2-1) =1 +1/(4k2-1) =1+ 1/[(2k-1)(2k+1)] =1+ ?[1/(2k-1) -1/(2k+1)] 22/(1×3)+ 42/(3×5) +62/(5×7)+ 82/(7×9) +102&
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