f(x) = ax³ - 2bx² + cx + 4d f'(x) = 3ax² - 4bx + c (1) f(-x) = - f(x) :a(-x)³ - 2b(-x)² + c(-x) + 4d = -(ax³ - 2bx² + cx + 4d) f(0) = 0:4d = 0 f'(-1) = 0:3a + 4b + c = 0 f(-1) = -2/3:-a - 2b - c + 4
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